Using z-scores, a population with µ = 37 and σ = 6 is standardized so that the new mean is µ = 50 and σ = 10. after the standardization, one individual has a score of x = 55. what was this individual’s score in the original distribution?

x = 43
it cannot be determined with the information given.
x = 40
x = 42

X = 40

Step-by-step explanation:

Original mean (µ) = 37

Original standard deviation (σ) = 6

New mean (µ) = 50

New standard deviation (σ) = 10

The z-score of an individual who had a score of X=55 in the new distribution is given by:

A z-score of 0.5, in the original distribution yields a score, X, of:

This individual’s score in the original distribution is X = 40

560

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