In a capture/recapture program, 30% of the animals recaptured have tags. suppose 70 animals were originally captured, tagged and released. estimate the population. round to the nearest whole number.

Approximately , there are 233 animals in the forest.

Step-by-step explanation:

There was a capture program of animals to get a count of the animals in that region.There were two rounds for that program. In the first round 70 animals were captured and all of them were tagged . In the second round , there were more animals caught but only 30% of those newly caught animals had tags.

Here we have to assume that no animal loses tag.

Let the total population be x .

Then 30% of the total population is 70.

Writing equation ,

x =233 animals

Approximately , there are 233 animals in the forest.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)