Mr john has a son and a daughter , the son being 4 years older than daughter. five years ago the age of mr john was 23 years more than the sum of ages of his son and daughter. after 18 years from now the age of mr john will be 17 times the difference of ages of his son and daughter. find their present ages?

First, let us define our variables.

Let

x = age of the father

y = age of the son

z = age of the daughter

5 years ago..

(x – 5) = age of the father

(y – 5) = age of the son

(z – 5) = age of the daughter

After 18 years...

(x + 18) = age of the father

(y + 18) = age of the son

(z +18) = age of the daughter

From the first condition

y = z + 5 à eqn 1

5 years ago

(x-5) = 23 + (y-5) + (z-5)

x –y –z = 18 à eqn 2

after 18 years

(x+18) = 17*[(y +18 –z – 18)]

x – 17y + 17z = -18 à eqn 3

solving the 3 equations simultaneously

x = 67

y = 27

z = 22

astronomers is your final answer! : )

total amount of money that he should pay if he has not used his duty free exemption is $98

step-by-step explanation:

given a united states citizen returning to the states declares the following items at the customs office: 3 shirts at $8.50 each 2 dresses at $27.50 each 1 pair of gold cuff links at $17.50 per pair. we have to find how much he pay

cost of 3 shirts if one cost at $8.50 is

cost of 2 dresses if one cost at $27.50 is  

cost of 1 pair of gold cuff at $17.50

so, total amount of money that he should pay if he has not used his duty free exemption is   $25.5+$55+$17.50=$98