How many area codes (abc) would be possible if all three digits could be any vaiue 1-9

The total number of area codes that would be possible if all three digits could be any value from 1 to 9 is 729.

Step-by-step explanation:

1. Let's start our reasoning to get this

From 000 to 999, we have 1,000 possible area codes.

But for this question, we should find out the answer without considering the digit 0, therefore we must exclude:

A. From 000 to 099, that are 100 possible area codes.

B. We also have to exclude, from 100 to 110, 120, 130, 140, 150, 160, 170, 180 and 190. Those are 19 area codes more.

C. We also have to exclude these same options of code areas, for 200 - 210 and 2x0, and 19 more for each subset that starts with 3, 4, 5, 6, 7, 8 and 9. In total, 19 multiplied by 8, 152 numbers more.

Therefore, the total number of area codes that would be possible if all three digits could be any value from 1 to 9 is:

1,000 - 100 - 19 - 152 = 729

The simplest way to find it, is:

For 000 to 999 = 1,000 or 10³

Excluding the digit zero = 729 or 9³

which expression can be used to convert 80 us dollars (usd) to australian dollars (aud)?

1 usd = 1.0343 aud

1 aud = 0.9668 usd

step-by-step explanation:

sorry just need the points

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.