Arectangle has a perimeter of 25 in. the length is four times the width. what are the dimensions of the rectangle
(create an equation! )

L = 10 in

W = 2.5 in

Step-by-step explanation:

Let length be L and width be W

Perimeter = L + L + W + W

Perimeter =2L + 2W

given than length is 4 times the width, or

L = 4W (substitute this back into the perimeter equation above)

Perimeter =2L + 2W

Perimeter =2(4W) + 2W

Perimeter =8W + 2W

Perimeter = 10W

given that the perimeter is 25in

25 = 10W

W = 25 / 10 = 2.5 in  (answer for width)

L = 4W = 4(2.5) = 10 in (answer for length)

20

step-by-step explanation:

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl