Suppose a ladder 20 feet long is placed against a vertical wall 20 feet high. how far would the top of the ladder move down the wall by pulling out the bottom of the ladder 5 feet? explain your reasoning.

Ugh h h t t u i i vick u

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So the first thing we do is to multiply the top equation by 3. the reason i want to do this is i notice there will be a 6y on both equations and can possibly add/subtract them. so we get 6y = -3x + 27. adding that and the second equation we get 6x = 27-15 which is 12. divide by 6 and we get 2. ∴ x = 2. substituting 2 into the first equation we get 2y = -2 + 9 which is 7. divide by 2 and we get 7/2. ∴ y = 7/2, x = 2.