How do write a line with point (7,9) and a slope of 1 in slope intercept form?

9 = 1(7) + 2

So generally it is:

y = x + 2  (I think this is the answer your teacher wants)

Step-by-step explanation:

y = mx + b is the slope intercept form equation

you know that 9 is one of your y points, so you can plug it in (9 = mx + b)

you also know that 7 is an x point, so you can plug it in as well (9 = m(7) + b)

then you can plug in your slope because you know that as well (9 = 1(7) + b)

to find your intercept, subtract your y point from the x point since there is a slope of one (you can only do this for a slope of one) you will get two as your intercept (9 = 1(7) + 2) this is your exact equation with that one point, but to generalize it so you could find any point, you would write: y = x + 2 (you don't include the slope because it is just one)

Hope this helped!

:D

a) t'(-3, 6) and v'(0, 3)  

step-by-step explanation: