Parallel to y= -2x + 3 passes through the point (-2, -1)

y = -2x - 5

Step-by-step explanation:

An equation of a line in slope-intercept is y=mx + b.

x and y are points on the line.

m is the slope.

b is the y-intercept.

To find this equation, we will need to find m and b.

When lines are parallel, they have the same slope.

A line parallel to y = -2x + 3 has a slope of -2.

m = -2

To find b, substitute into the equation a point on the line (-2, -1) and m = -2.

A point is in the form (x, y). So x = -2, y = -1.

y = mx + b

-1 = (-2)(-2) + b  Simplify by multiplying the (-2)(-2)

-1 = 4 + b   Subtract 4 from both sides to isolate b

-5 = b

b = -5   Writing the variable on the left side is standard formatting

Since we now know the y-intercept, b= -5, and the slope, m = -2, substitute them into y=mx + b to get the equation of the line.

y = -2x - 5

i need points

step-by-step explanation:

sorry bubs