F(x)=\begin{cases}-(x-2)^2-3 & \text{ for }\hspace{10px} x< 4 \\ -5 & \text{ for }\hspace{10px} x=4 \\ \frac{1}{2}x-10 & \text{ for }\hspace{10px} x> 4\end{cases} f(x)= ⎩ ⎪ ⎨ ⎪ ⎧ −(x−2) 2 −3 −5 2 1 x−10 for x< 4 for x=4 for x> 4

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

answer: 12

step-by-step explanation:

because yes

i need points

step-by-step explanation:

sorry bubs