Assuming that the equation defines x and y implicitly as differentiable functions xequals=f(t), yequals=g(t), find the slope of the curve xequals=f(t), yequals=g(t) at the given value of t. x^3+3t^2 =13, 2y^3−3t^2= 42, t=2. the slope of the curve at t=2 is what?

Step-by-step explanation:

Given that x and y are implicitly as differentiable functions.

xequals=f(t), yequals=g(t),

we have to get value of x and y at t =2

we have to find the slope of the curve at t=2

i.e. we have to find

= at t=2

Substitute the values of x and y and also t in these equations to get

Slope =

the correct answer is d

hope this

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1