Fthe probability of being hospitalized during a year is 0.25 , find the probability that no one in a family of five will be hospitalized in a year.

The probability that no one in a family of five will be hospitalized in a year is 0,2373

Step-by-step explanation:

Let p denote the probability of being hospitalized during a year,

Then p=0.25

And p' the probability of not being hospitalized during a year is 1-p

Thus p' = 1-p = 1-0.25 = 0.75

The probability that no one in a family of five will be hospitalized in a year is equal to . That is

= ≈ 0,2373

answer: 2 and 1

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answer: a video game has three difficulty levels: easy, medium, and expert. the game's scoring works in such a way that a player has to score a fixed number of points to advance to the next level, and then the scoring starts over. the total score needed to clear all three difficulty levels is 7,500. two times the number of points needed to clear the easy level is 500 more than the number of points needed to clear the medium level. twice the number of points needed to clear the medium difficulty level is 1,500 more than the number of points needed to clear the expert level. if x, y, and z represent the easy, medium, and expert levels, respectively, and a is the coefficient matrix of the system of equations modeling this situation, identify the inverse matrix, a-1, and the solution matrix, x, of the system of equations.

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