Which statements are true about the ordered pair (-1,-4) and the system of equations?

x-y=3

7x-y=-3

question 1 options:

when (-1,-4) is substituted into the first equation, the equation is false.

when (-1,-4) is substituted into the first equation, the equation is true.

when (-1,-4) is substituted into the second equation, the equation is false.

when (-1,-4) is substituted into the second equation, the equation is true.

the ordered pair (-1,-4) is a solution to the system of linear equations

the ordered pair (-1,-4) is not a solution to the system of linear equations.

When (-1,-4) is substituted into the first equation, the equation is true.

When (-1,-4) is substituted into the second equation, the equation is true.

Step-by-step explanation:

The given system is

x-y=3

7x-y=-3

Make x the subject in the top equation to get:

x=y+3

Put x=y+3 in the bottom equation to get:

7(y+3)-y=-3

Expand

7y+21-y=-3

7y-y=-3-21

6y=-24

y=-4

Put y=-4 into x=y+3 to get

x=-4+3=-1

Hence the point (-1,-4) is a solution to both equation

10 * 563.67 = 5636.7

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)