Ineed with this and fast if possible

The answer is Hence Proved

Step-by-step explanation:

       Given that CB║ED ,  CB ≅ ED

       To prove Δ CBF ≅ Δ EDF

        This means that the length of CB is equal to ED

        As CB║ED The following conditions satisfies when a transversal cut

        two parallel lines

       ∴ Δ CBF ≅ Δ EDF    ( By ASA criterion)

        The Δ CBF is congruent to Δ EDF By ASA criterion .

       Hence proved

a) one student is chosen from classroom a, then a student is chosen from classroom b.  

step-by-step explanation:

independent events are ones in which the probability of one event does not affect the probability of the second event.

one student is chosen from classroom a; this does not affect the chances of choosing a student from classroom b.   this makes these independent events.

when one card is chosen from a standard deck and then set aside before a second card is chosen, the probability of the second card being chosen changes.   this makes them dependent events.

when one student is chosen from classroom a and then a second student is chosen from classroom a, the probability of choosing the second student changes.   this makes them dependent events.

when a letter is chosen from the alphabet and then a second letter is chosen, the probability of choosing the second letter changes.   this makes them dependent events.