What is the cost for the problem below

it will cost $3190.752

Step-by-step explanation:

Step 1

We would determine the length of the side of the field, AC. To do this, we would apply the cosine rule. Since we know sides AB and BC and angle B, It will be expressed as

b^2 = a^2 + c^2 - 2acCosB. It becomes

b^2 = 320^2 + 450^2 - 2×320×450Cos80

= 102400 + 202500 - 144000Cos80

= 304900 - 24998.4

b^2 = 279901.6

b= √279901.6

b = 529.06 yards

Step 2

We would determine the area of the triangle. The formula for the area of the triangle is expressed as

Area of triangle = 1/2 × acSinB

Area of triangle = 1/2 × 320 × 450 × Sin 80

Area of triangle = 72000 × 0.9848 = 70905.6 yards^2

If 100 square yards cost $4.50

70905.6 square yards cost (70905.6×4.5) /100 = $3190.752

7.3

step-by-step explanation:

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}