Asquare field had 3 m added to its length ad 2 m added to its width. the field then had an area of 90 m squared. find the length of a side of the original field.

The length of a side of the original field  = 7 m.

Step-by-step explanation:

Here, the initial field is in form of a square.

Let us assume the side of the original square field = k meters

Now, the new length of the field = ( k + 3)  m

The new width of the field = ( k + 2) m

So, the new field is now a rectangle with area  = 90 sq. m

AREA OF A RECTANGLE  = LENGTH x WIDTH

Here, the area of the new field  =  New length x new width

                                                      =   ( k + 3) x ( k + 2)

⇒ either (k +12) = 0 ⇒  k = -12

or, ( k-7) = 0 ⇒  k = 7

But, here k = SIDE OF A FIELD, and it CANNOT be negative.

⇒  k = 7

Hence, the length of a side of the original field  = 7 m.

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step-by-step explanation:

its wrong

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !