Raven built a rocket for her science project and launched it from a platform to track its path. the hight in feet of the rocket above ground at time t seconds can be modeled by the equation h= -16t^2+32t+4 what is the maximum hight the rocket reaches

20ft

Step-by-step explanation:

-16t² + 32t + 4

The main goal to find the maximum height is to find the vertex of the parabola because the vertex is always the minimum or the maximum value.

To find the x value of the vertex, use the formula x =

The a-value is the first coefficient and the b value is the second coefficient:

x =

x = 1

We can say x = t because t is the x value in the equation.

Now, we can substitute x back into the original equation to find the y-value for the vertex.

y = -16t² + 32t + 4

y = -16(1)² + 32(1) + 4

y = -16(1) + 32 + 4

y = -16 + 32 + 4

y = 20

In a word problem, height is typically the y-value and time is typically the x-value. Since t = x, the answer is 20.

mental cunning

explanation:

he is often referred to as a man of twists and turns

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.