Enter the polynomial function with the least degree and a leading coefficient of 1 that has the given
zeros. enter your answer in standard form.
1,-1(multiplicity 3), and 3i

Step-by-step explanation:

if a, b, c are the zeros of a polynomial, then the equation of the curve with leading  coefficient of 1 or the  polynomial function  with leading coefficient of 1 f(x) can be written as : (x-a)* (x-b)* (x-c).here, the given zeros are : 1, -3 , 3iso, the polynomial function f(x) = (x-1)* (x-(-3))* (x-3i).

=(x-1)* (x+3)* (x-3i)

=

thus, the polynomial function with the least degree and a leading coefficient of 1 that has the zeros : 1,-1(multiplicity 3), and 3i  is

Recall that area of the triangle is 1/2*(base)*(height)1/2*(13)*(17) = 110.5the answer is 110.5