What is the solution to –2(8x – 4) < 2x + 5?

a. x > x is greater than startfraction 1 over 6 endfraction.
b. x < x is less than startfraction 1 over 6 endfraction.
c. x > 6
d. x < 6

x>1/6

Step-by-step explanation:

-2(8x-4)<2x+5

-16x+8<2x+5

-16x-2x+8<5

-18x+8<5

-18x<5-8

-18x<-3

18x<3

x<3/18

x<1/6

x>1/6

15.5

step-by-step explanation:

5

∑

n = 1

substitute n = 1, 2, 3, 4, 5 and sum the terms

= + + + 2² + 2³

= 0.5 + 1 + 2 + 4 + 8

= 15.5

third option: 6x+8

step-by-step explanation:

we can see that the given question is a sum of series and the values of n vary from 0 to 3

the first term will be:

when n=0, [(0)*x+2] => (0+2) => 2

when n=1, [(1)*x+2] => (x+2) => x+2

when n=2, [(2)*x+2] => 2x+2

when n=4, [(3)*x+2] => 3x+2

so adding up all the terms will give us:

=2+x+2+2x+2+3x+2

=x+2x+3x+2+2+2+2

=6x+8

so,

third option is the correct answer ..