A100 foot rope weighs 200 pounds. it is hanging vertically from the top of a tall building. after "x" feet have already been lifted, how much does the remainder of the rope (the hanging part) weigh? o2 pounds 200 pounds o2(100 – 2 pounds

2*(100-X)

Step-by-step explanation:

Total length = 100 ft

Total weight =200 pounds

Assuming that the rope has an uniformly distributed weight, its weight per feet is:

If "x" feet have already been lifted, the length left to be lifted is 100 - x.

Therefore, the weight of the remainder of the rope is:

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

answer: 7

step-by-step explanation: