Aline passes through the points (4, 19) and
(9,24). write a linear function in the form
y= mx + b for this line.

  y = x+15

This is the same as y = 1x+15

Work Shown:

The two given points are

(x1,y1) = (4,19)

(x2,y2) = (9,24)

Use the slope formula

m = (y2-y1)/(x2-x1)

m = (24 - 19)/(9-4)

m = 5/5

m = 1

The slope is 1.

Pick one of the points and plug those coordinates into y = mx+b along with m = 1. I'll plug (x,y) = (4,19) into the equation

y = mx+b

19 = 1*4+b

19 = 4+b

4+b = 19

b+4 = 19

b+4-4 = 19-4 ... subtract 4 from both sides

b = 15

m = 1 and b = 15 makes y = mx+b turn into y = 1x+15 or simply y = x+15

a) 7x=7

step-by-step explanation:

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.