Amedical resident is convinced that, on average, residents at his hospitals work for over 3 hours more per week than residents at other hospitals. suppose that he finds that a random sample of 30 residents at his hospital works an average of 74.3 hours per week with a standard deviation of 2.6 hours. he also surveys a random sample of 30 residents working at other hospitals and finds they worked an average of 70.1 hours per week with a standard deviation of 2.9 hours. do the data support the resident’s belief? test the relevant hypotheses at a significance level of 0.05.

At 0.05 significance level, there is significant evidence that residents at the medical resident's hospitals work for over 3 hours more per week than residents at other hospitals.

Step-by-step explanation:

:residents at the medical resident's hospitals work for 3 hours more per week than residents at other hospitals

:residents at the medical resident's hospitals work for over 3 hours more per week than residents at other hospitals.

Test statistic can be calculated using the formula:

z= where

z= ≈ 1.6875

P-value of the test statistic is   0.046. Since  0.046>0.05 we reject the null hypothesis.

21.4 i did it already for s1

step-by-step explanation:

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square