Solve the following initial value problems (ivp) using the modified euler’s method with a) the average derivative and b) the derivative at midpoint: 1. dy dx = 4y x , subject to: y(1) = 2 → y(x) = 2x 4 2. dy dx = −2y − x, subject to: y(0) = −1 → y(x) = 2 − 3e −x − 2x integrate over the interval x = [1, 3] for the first ivp and over x = [0, 3] for the second ivp using 4 and 5 intervals. you will use the given true solution to determine the absolute error of the methods.

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

dude thats to long figure it

step-by-step explanation:

the answer is $42.96

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