solve linear-quadratic system algebraically. then what is the x coordinate of the solution? show all work.

y = x^2 + 1
y – 1 = x

the x coordinate of the solution is 1

Step-by-step explanation:

y = x^2 + 1 - - - - - - 1

y – 1 = x - - - - -2

From equation 2 , y = x + 1

Substituting y = x + 1 into equation 1, it becomes

x + 1 = x^2 + 1

x^2 + 1 - x - 1 = 0

x^2 - x - 1 + 1 = 0

x^2 - x = 0

Let x be on the right hand side of the equation and x^2 remains on the left hand side of the equation. It becomes

x^2 = x

Dividing the left hand side of the equation and the right hand side of the equation by x, it becomes

x^2/x = x/x

x = 1

Therefore, x = 1

22.83 repeating

step-by-step explanation:

137 ÷ 6 is 22.8333333 therefore we understand that 3 is repeating.

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