Tv advertising agencies face increasing challenges in reaching audience members because viewing tv programs viadigital streaming is gaining in popularity. the harris poll reported on november 13, 2012, that 53% of 2343 americanadults surveyed said they have watched digitally streamed tv programming on some type of devicea. calculate and interpret a confidence interval at the 99% confidence level for the proportion of all adult americans whowatched streamed programming up to that point in time." 9b. what sample size would be required for the width of a 99% c | to be at most .05 irrespective of the value p .

Let p denotes the population proportion of all adult Americans who watched streamed programming up to that point in time.

Given : The Harris poll reported on November 13, 2012, that 53% of 2343 American adults surveyed said they have watched digitally streamed TV programming on some type of devices.

i.e.  sample size :n= 2343

We know that ,

Critical value for 99% confidence interval =

a) Confidence interval for population proportion:-

i.e. Confidence interval : (0.5035, 0.5565)

Interpretation: A person can be 99% confident that the true proportion of all adult Americans who watched streamed programming up to that point in time lies between 0.5035 and 0.5565 .

b) Margin of error : E= half of width of CI=

The formula to find the sample size  , if the prior estimate of population proportion is known:

Put all the value in the above formula :

Thus , the minimum sample size = 2645

(0.2)+(-8)=0.3+-3+0.3m is the equation i guess? ?

step-by-step explanation: