3x^2-12x-3
how do i factor this function?

Step-by-step explanation:

Take the -3 out:

-3(x^2 +4x+1)

It's best to use the quadratic formula in this case:

(-b±√b²-4ac)/2a

where a =1, b =4, c=1

(-4 ±√16 -4)/2(1)

when you do (-4+√16 -4)/2(1), you will get  -2+√3 = -0.2679..

when you do (-4-√16 -4)/2(1), you will get -2-√3= -3.732..

So, the factored form would look like:

-3(x-2+√3)(x-2-√3)

Hope this helps!

Would really appreciate the brainliest if you think i helped!

ddd

step-by-step explanation: