A6000-seat theater has tickets for sale at $28 and $40. how many tickets should be sold at each price for a sellout show to generate a total revenue 194400
the number of tickets for sale at $28 should be
the number of tickets for sale at $40 should be

3,833 for $28

2167 for $40

Step-by-step explanation:

Let X be the number of tickets sold at the price of $24, And Y be the number of tickets sold at the price of $40.

Now,   $ 28X will be the revenue generated due to the $28 tickets

And,   $40Y will be the revenue generated due to the 40$ tickets.

Now, Total revenue generated should be $194400.

Thus ,   28X + 40Y  = 194400  -(1).

Also,

Total number of seats in theater is 6000.

So, X + Y = 6000.  -(2)

X = 6000 - Y.

Put in equation 1

We get ,    168,000 - 28Y + 40Y = 194,400

                   12Y = 26,000

                      Y = 2,166.66

Since , Y is of 40 $ so minimum tickets sold should be 2167.

X = 3,833.

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

one more happy customer!

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step-by-step explanation:

30 people weigh 160 pounds or more