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What is the value of c so that -9 and 9 are both solutions of x^2 + c = 103?
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Solve the equation below: (x+4)/6x=1/x a. x=2 b. x=0,2 c. x=-2 d. x=0,-2
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Which of the points a(6, 2), b(0, 0), c(3, 2), d(−12, 8), e(−12, −8) belong to the graph of direct variation y= 2/3 x?
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What is the value of c so that -9 and 9 are both solutions of x^2 + c = 103?...
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