Rover eats 3/4 of a can of cat food each day and bono eats 1/2 of a can food each day. cat food costs $5.00 for three cans. it is only sold in 3 can packs. how much does it cost for a 60 day supply of cat food?

It would Cost $125 for a 60 day supply of cat food.

Step-by-step explanation:

Given:

Rover eats cat food each day = = 0.75 can

Bono eats cat food each day = = 0.5 can

Each day consumption for both cats = 0.75+0.5 = 1.25 can

Each day both cats consume = 1.25 cans

For 60 days both cats consume = Number of cans in 60 days.

By Using Unitary method we get;

Number of cans in 60 days =

Now Cans are sold in a pack of 3.

Hence we will divide number of cans in 60 days with 3 we get;

Number of can packs required for 60 days =

Now Cost for each Can packs(3 can) = $5.00

Hence Cost for 25 Can packs (75 cans) = Price for 25 can packs(75 can)

By Using Unitary method we get;

Price for 25 can packs (75 cans) =

Hence Price for 25 can packs (75 cans) which are used for 60 supply of cat food is $125.

$27.5

step-by-step explanation:

$110.00 divided by 4

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form