The average hourly wage of workers at a fast food restaurant is $6.75 with a standard deviation of $0.25. if the distribution is normal, what is the probability that a worker selected at random earns more than $7.00 an hour?

25% would be the answer

Step-by-step explanation:

its a straight line parallel to the time axis

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b