90 points

one zero of the polynomial function f(x) = x3 − x2 − 20x is x = 0. what are the zeros of the polynomial function?

\Given :

x^{3} +x^{2} -20x

Solution:

x^{3} +x^{2} -20x

taking x common from the given polynomial

⇒x(x^{2} +x-20)=0

⇒x(x(x+5)-4(x+5))=0

⇒x(x+5)(x-4)=0

⇒ x=0 , x+5=0 , x-4=0

⇒x = 0 , x = -5 , x = 4

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triangle and cube

step-by-step explanation: