Jacob went on a bike ride. after 10 miles he got a flat tire and had to jog back home. he jogs 5 mph slower than he bikes, so the jog took 1 hour longer than the bike ride. at what rate did he travel each way?

He traveled 10 km/hr through bike and 5km/hr by jogging.

Step-by-step explanation:

Let the speed of bike be 'x'.

Let the speed of his jogging be 'x-5'.

Distance covered = 10 miles

So the jog took 1 hour longer than the bike ride.

According to question, we get that

Hence, he traveled 10 km/hr through bike and 5km/hr by jogging.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate