Can y’all me with #15 ? how do i set it up ?

Find the arc length parameter along the given curve from the point where tequals=0 by evaluating the integral s(t)equals=integral from 0 to t startabsolutevalue bold v left parenthesis tau right parenthesis endabsolutevalue d tau∫0tv(τ) dτ. then find the length of the indicated portion of the curve r(t)equals=1010cosine tcost iplus+1010sine tsint jplus+88t k, where 0less than or equals≤tless than or equals≤startfraction pi over 3 endfraction π 3.

Solve the word problem. the table shows the low outside temperatures for monday, tuesday, and wednesday. by how many degrees did the low temperature increase from monday to tuesday? this function table shows the outside temperature for a given a. 21.1⁰ b. 8.6⁰ c. 4.9⁰ d. 3.9⁰(the picture is the graph the the question is talking about.)

896.31 cm= km 100cm = 1m 1000m = 1km a) 0.0089631 b) 0.0089631 c) 8.9631 d) 89.631