The area of a rectangular room is 750 square feet. the width of the room is 5 feet less than the length of the room.

which equations can be used to solve for y, the length of the room? check all that apply.

y(y + 5) = 750
y2 – 5y = 750
750 – y(y – 5) = 0
y(y – 5) + 750 = 0
(y + 25)(y – 30) = 0

Option B , C  and E are correct

(y+25)(y-30)=0

Step-by-step explanation:

Given : Area of rectangular room is 750 square feet.

Width of the room is 5 feet less than the length of the room.

Let y be the length of the room

then,

As per the given condition

width of the room is: y-5

Area of rectangle is multiply the length by its width.

Area of rectangle =

Substitute the given values in above formula we get;

                           ......[1]

or we can write this as;

750 -y(y-5)=0

[1] ⇒  or

or

(y+25)(y-30)=0

Therefore, the equation which can be used to solve for y are;

,  and (y+25)(y-30)=0