The graph of which of the following will be perpendicular to the graph of 4x- 3y= -12
a. 4x+3y=12
b. y=-3/4x-8
c. y=3/4x+1
d. 3x-4y=1

(b) y=-3/4x-8

Step-by-step explanation:

The graph that will be perpendicular to the graph 4x - 3y = -12

If this equation is represented in form of the straight line equation y = mx + b

it will change to 3y = 4x + 12

therefore y = (4/3)x + (12/3)

y = (4/3)x + 4

which implies that m = 4/3 while b = 4

However for the line that will be perpendicular to the graph, its slope m1 must be negative inverse of the slope of the initial graph

This is because m x m1 = -1

therefore m1 = -1/m

this implies that the correct answer must have a slope of -1/(4/3) = -3/4

The correct answer can then be analysed by expressing all options with y = mx + b

(a) In form of y = m1x + b, 4x+3y=12 becomes y = -4/3x + 4 (m1 = -4/3: wrong)

(b) In form of y = m1x + b, y=-3/4x-8 has m1 = -3/4 (correct)

(c) In form of y = m1x + b, y=3/4x+1 has m1 = 3/4 (wrong)

(d) In form of y = m1x + b, 3x-4y=1 becomes y = 3/4x - 1/4 (m1 = 3/4: wrong)

answer: 48

just remember to use pemdas:

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