What is the equation of the line that has a slope of -4 and goes through (-1,6)?
a. y + 6 = -4(x + 1)
b.
y + 6 = -4(x - 1)
c.
d.
y-6 = -4(x + 1)
y - 6 = -4(x - 1)

y-6=-4(x+1)

Step-by-step explanation:

y-y1=m(x-x1)

Where m=slope and (x1, y1) is a point on the line.

m=-4

y-6=-4(x-(-1))

y-6=-4(x+1)

C. y − 6 = -4(x + 1)  

Step-by-step explanation:

I got it right in a test.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

part a: 1.08

part b: 27.59