Find all the solutions in there interval (0,2pi) for cos5x=-1/2

Step-by-step explanation:

Solving trigonometric equations.

We are given a condition and we must find all angles who meet it in the provided interval. Our equation is

Solving for 5x:

The values for x will be

To find all the solutions, we'll give n values of 0, 1, 2,... until x stops belonging to the interval

For n=0

For n=1

For n=2

For n=3

For n=4

For n=5 we would find values such as  

which don't lie in the interval

The whole set of results is

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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my dear correct answer is option number 3