The math and verbal sat scores for a random sample of 10 students from a large introductory statistics course are provided. student 1 2 3 4 5 6 7 8 9 10 11 12 math sat 640 620 700 680 600 720 770 580 660 580 655 63.1 verbal sat 580 690 560 560 600 700 620 620 710 500 614 68.8 differences (math - verbal) 60 -70 140 120 0 20 150 -40 -50 80 41 81.0 which data analysis method is more appropriate in this situation: paired data difference in means or difference in means with two separate groups? explain briefly.

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%

853.3

step-by-step explanation:

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²

answer: he is 272195

step-by-step explanation: all you have to do is multiple 3535 and 77 and it equals 272195