Charlie’s pizza charges $12 for a medium cheese pizza plus $2 for each additional topping. the cost of a medium pizza, y, with x toppings is represented by this equation:

y = 12 + 2x

which graph represents this equation?

The correct answer is Graph A. It's the only graph with the right values for (x, y) within the Cartesian plane.

Step-by-step explanation:

1. Let's review the data given to us for solving the question:

Amount that Charlie’s pizza charges for a medium cheese pizza = US$ 12

Amount that Charlie’s pizza charges for each additional topping = US$ 2

Cost of a medium pizza (y) with (x) toppings is represented by the equation:

y = 12 + 2x

2. Let's find the values for the equation:

When no toppings are added:

y = 12 + 2 * 0 = 12 + 0 = 12

When 1 topping is added:

y = 12 + 2 * 1 = 12 + 2 = 14

When 2 toppings are added:

y = 12 + 2 * 2 = 12 + 4 = 16

When 3 toppings are added:

y = 12 + 2 * 3 = 12 + 6 = 18

When 4 toppings are added:

y = 12 + 2 * 4 = 12 + 8 = 20

As we can see, the graph starts with the point (0, 12) and continues with (1, 14), (2, 16), (3, 18), (4, 20).  

Graph B starts with the point (0, 4) and graph C with the point (0,6). They're incorrect. And graph D starts with (0, 12) but continues with (1, 13), (2, 14) (3, 15) and (4, 16), so this graph is also incorrect.

The only graph with the right values for the Cartesian plane is Graph A.

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

i’m here for points.