Which equation has the solutions x = -3 ± √3i/2 ?

2x2 + 6x + 9 = 0
x2 + 3x + 12 = 0
x2 + 3x + 3 = 0
2x2 + 6x + 3 = 0

Answer is option C : [ + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "".  

Here, First thing you have to observe the nature of roots.

∴ x = -+i and x = --

∴ [ x+(-i) ][ x+(+i) ]=0

∴ [ + x(+i)+ x(-i) + (-i)(+i) ]=0

∴ [ + x + ix + x - ix + (3-i)(3+i) ] =0

∴ [ + 3x + (-i)(+i) ] =0

∴ [ + 3x + - (i)(i) ] =0

∴ [ + 3x + - () ] =0

∴ [ + 3x + + () ] =0

∴ [ + 3x + ] =0  

∴ [ + 3x + 3 ] =0  

Thus, Answer is option C : [ + 3x + 3 ] =0  

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

could you provide figure.