The balance in two separate bank accounts grow each month at different rates. the growth rates for both accounts are represented by the functions f(x)=3^x and g(x)=5x+25. in what month is the f(x) balance greater than the g(x) balance? show your work!

From fourth month onwards, the growth rate of is greater than that of .

Step-by-step explanation:

Given:

The growth rates of both bank accounts are given as:

Now, as per question, we need to find the value of 'x' when the value of . Or,

Now, we can do this by checking the values of 'x' by hit and trial method.

Let . The inequality becomes:

Let . The inequality becomes:

Let . The inequality becomes:

Let . The inequality becomes:

Therefore, the value of 'x' for which is 4.

So, from the fourth month onwards, the balance in becomes greater than .

The graphical solution is shown below to support the same.

From the graph, we can conclude that after the 'x' value equals 3.4, the graph of lies above of . Hence, for

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.