What is the slope of a line that is perpendicular to the line whose equation is y=4x+1?

Step-by-step explanation:

The equation of a straight line can be represented in the slope-intercept form, y = mx + c

Where c = y intercept

Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis

From the information given,

comparing the equation given,

y=4x+1 with the slope intercept equation, y = mx + c

Slope, m = 4

When two slopes are perpendicular, their product is -1

Let the slope of the perpendicular line to the one given by the above equation be m1. Therefore,

m × m1 = -1

4 m1 = -1

m1 = -1/4

Inputting m1 = 4 into the slope intercept equation, it becomes

y = -1/4×x + c

y = -x/4 + c

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