Prove lo bisects angle mln and identify which given statement is unnecessary.

Given:

LM = LN, KM = KN, KO bisects angle MKN

What we want to prove:

LO bisects angle MLN

Proof:

Statement 1: KM = KN

Reason 1: Given

Statement 2: KO bisects angle MKN

Reason 2: Given

Statement 3: Angle MKO = Angle NKO

Reason: Definition of angle bisection

Statement 4: KO = KO

Reason 4: Reflexive property of congruence

Statement 5: Triangle MKO = Triangle NKO

Reason 5: SAS postulate

note: this combines statements 1, 3, and 4 (for the "S", "A", and "S" in that order)

Statement 6: MO = ON

Reason 6: CPCTC

note: CPCTC stands for "corresponding parts of congruent triangles are congruent"

Statement 7: Angle KOM = Angle KON

Reason: CPCTC

Statement 8: OL = OL

Reason 8: Reflexive property of congruence

Statement 9: Triangle MOL = Triangle NOL

Reason 9: SAS postulate

note: used statements 6, 7, 8 for the "S", "A", "S" in that order

Statement 10: Angle MLO = Angle NLO

Reason 10: CPCTC

Statement 11: LO bisects angle MLN

Reason 11: Definition of angle bisection

That concludes the proof. We did not use the statement "LM = LN", so it is unnecessary.

step-by-step explanation:

vyv6vycyctxrd4ff6fg yr x5dc v6y555 vyuvu

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!