Box a has a volume of 32 cubic meters. box b is similar to box a. to create box b, box a's dimensions were tripled. what is the volume of box b?
a. 864 m3
b. 288 m3
c. 96 m3
d. 32 m3

The correct option is A.

Step-by-step explanation:

It is given that the volume of box A is 32 cubic meters.

Let dimensions of the box A are l×b×h.

It is given that the dimensions of the box B were tripled than box A. So the dimensions  of the box B are 3l×3b×3h.

The volume of box A is

            ...(1)

Where, l is length, b is breadth and h is height.

The volume of box B is

Using equation (1), we get

The volume of box B is 864 cubic meter. Therefore the correct option is A.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2