Eduardo, sarah, maria, jim, and tyrone have all been invited to a dinner party. they arrive randomly and each person arrives at a different time.
a. in how many ways can they arrive?
b. in how many ways can eduardo arrive first and tyrone last?
c. find the probability that eduardo will arrive first and tyrone last.

a. 120

b. 6

c. 0.05

Step-by-step explanation:

a) The ways Eduardo, Sarah, Maria, Jim, and Tyrone can arrive to the party is

5! = 5×4×3×2×1 = 120

The logic behind it is

b) Using the same logic, when first and last arrived is known, there is

3!=3×2×1=6 ways they can arrive in this case.

c)  The probability that Eduardo will arrive first and Tyrone last is

the division of the ways Eduardo arrive first and Tyrone last by the ways 5 people can arrive

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation: