Solve the following system of equations:
−2x + y = 1
−4x + y = −1
a- (3, 1)
b- (−1, 3)
c- (−1, −3)
d- (1, 3)

x = 1 , y = 3 thus D: is your answer

Step-by-step explanation:

Solve the following system:

{y - 2 x = 1 | (equation 1)

y - 4 x = -1 | (equation 2)

Swap equation 1 with equation 2:

{-(4 x) + y = -1 | (equation 1)

-(2 x) + y = 1 | (equation 2)

Subtract 1/2 × (equation 1) from equation 2:

{-(4 x) + y = -1 | (equation 1)

0 x+y/2 = 3/2 | (equation 2)

Multiply equation 2 by 2:

{-(4 x) + y = -1 | (equation 1)

0 x+y = 3 | (equation 2)

Subtract equation 2 from equation 1:

{-(4 x)+0 y = -4 | (equation 1)

0 x+y = 3 | (equation 2)

Divide equation 1 by -4:

{x+0 y = 1 | (equation 1)

0 x+y = 3 | (equation 2)

Collect results:

{x = 1 , y = 3

27 +27 or 27times 2=54

the diffrence is 0