What is the horizontal asymptote of the function f(x)=((x-2))/((x-3)^(2))

y = 0

Step-by-step explanation:

f(x) = (x − 2) / (x − 3)²

Take the limit as x approaches -∞ and ∞.  Since the power of the denominator is greater than the power of the numerator, both limits are 0:

lim(x→-∞) f(x) = 0

lim(x→∞) f(x) = 0

So the horizontal asymptote is y = 0.

your answer is a

step-by-step explanation:

4*4*4*4=256

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47