Arental moving truck can haul a maximum of 7,500 pounds. dejuan has boxes that weigh 40 pounds and boxes that weigh 75 pounds. how many of each kind of box can he haul in one load?

if x represents the number of 40-pound boxes and y represents the number of 75-pound boxes, which graph correctly shows the solution to the problem? (2 points)

a
x, y graph. x range is negative 300 to 300, and y range is negative 300 to 300. dashed line on graph has negative slope and runs through 0, 100 and 187.5, 0. below line is shaded.

b
x, y graph. x range is negative 300 to 300, and y range is negative 300 to 300. solid line on graph has negative slope and runs through 0, 100 and 187.5, 0. below line is shaded.

c
x, y graph. x range is negative 300 to 300, and y range is negative 300 to 300. solid line on graph has negative slope and runs through 0, 100 and 187.5, 0. above line is shaded.

d
x, y graph. x range is negative 300 to 300, and y range is negative 300 to 300. dashed line on graph has negative slope and runs through 0, 100 and 187.5, 0. above line is shaded.

Cone w has a radius of 8 cm and a height of 5 cm. square pyramid x has the same base area and height as cone w. paul and manuel disagree on how the volumes of cone w and square pyramid x are related. examine their arguments. which statement explains whose argument is correct and why? paul manuel the volume of square pyramid x is equal to the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is three times the volume of cone w. this can be proven by finding the base area and volume of cone w, along with the volume of square pyramid x. the base area of cone w is π(r2) = π(82) = 200.96 cm2. the volume of cone w is one third(area of base)(h) = one third(200.96)(5) = 334.93 cm3. the volume of square pyramid x is (area of base)(h) = (200.96)(5) = 1,004.8 cm3. paul's argument is correct; manuel used the incorrect formula to find the volume of square pyramid x. paul's argument is correct; manuel used the incorrect base area to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect formula to find the volume of square pyramid x. manuel's argument is correct; paul used the incorrect base area to find the volume of square pyramid x.

Tell whether the two rates form a proportion

Asequence is a function whose is the set of natural numbers