1. you have two cards with a sum of (-12) in your hand.

a. what two cards could you have?

The required cards can be -6 and -6.

Step-by-step explanation:

Consider the provided integer -12.

We need to find the two cards whose sum is -12.

There are lots of choices for the two cards whose sum is -12.

Few choices are:

If we first card is -6 and the second card is also -6 then the sum will be -12:

If we first card is -4 and the second card is -8 then the sum will be -12:

If we first card is -10 and the second card is -2 then the sum will be -12:

Thus, the required cards can be -6 and -6.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b