Mathematics, 29.11.2019 05:31 crystalclear99
15 different tasks are assigned to 8 different people. there are no restrictions on the number of tasks that can be given to any one person. how many ways are there to assign the tasks? note that who gets which task is important.
Answers: 3
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Prove (a) cosh2(x) − sinh2(x) = 1 and (b) 1 − tanh 2(x) = sech 2(x). solution (a) cosh2(x) − sinh2(x) = ex + e−x 2 2 − 2 = e2x + 2 + e−2x 4 − = 4 = . (b) we start with the identity proved in part (a): cosh2(x) − sinh2(x) = 1. if we divide both sides by cosh2(x), we get 1 − sinh2(x) cosh2(x) = 1 or 1 − tanh 2(x) = .
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Mathematics, 22.06.2019 01:00
Given right triangle a w/a hypotenuse length of x+4 and a leg of x, and right triangle b, w/ a hypotense length of 3y and a leg length of y+4 for what values of x and y are the triangles congruent by hl?
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15 different tasks are assigned to 8 different people. there are no restrictions on the number of ta...
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