We now have lim x → [infinity] (4x − ln(x)) = lim x → [infinity] 4x 1 − ln(x) 4x . let's first focus on lim x → [infinity] ln(x) 4x . since ln(x) → [infinity] as x → [infinity], then this limit is indeterminate of type [infinity]/[infinity]. using l'hospital's rule, we find: lim x → [infinity] ln(x) 4x = lim x → [infinity] 1 = 0 .

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

2 1/2 feet

step-by-step explanation: